Tuesday, January 27, 2009

How do I load an org.w3c.dom.Document from XML in a string?

The entire header of this message and it's contents were copied from http://stackoverflow.com/questions/33262/how-do-i-load-an-orgw3cdomdocument-from-xml-in-a-string with one aim: to give higher rank for the page in Google PageRank.

Good reason for this is that good things should be replicated.

I have a complete XML document in a string and would like a Document object. Google turns up all sorts of garbage. What is the simplest solution? (In Java 1.5)

Solution Thanks to Matt McMinn, I have settled on this implementation. It has the right level of input flexibility and exception granularity for me. (It's good to know if the error came from malformed XML - SAXException - or just bad IO - IOException.)

public static org.w3c.dom.Document loadXMLFrom(String xml)
throws org.xml.sax.SAXException, java.io.IOException {
return loadXMLFrom(new java.io.ByteArrayInputStream(xml.getBytes()));

public static org.w3c.dom.Document loadXMLFrom(java.io.InputStream is)
throws org.xml.sax.SAXException, java.io.IOException {
javax.xml.parsers.DocumentBuilderFactory factory =
javax.xml.parsers.DocumentBuilder builder = null;
try {
builder = factory.newDocumentBuilder();
catch (javax.xml.parsers.ParserConfigurationException ex) {
org.w3c.dom.Document doc = builder.parse(is);
return doc;

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